Fill in the below method so that, when executed, it
reads an integer
n from the user and displays the positive even integers that are less
than or equal to n, in ascending order.
Following is a sample transcript illustrating how
an execution of the method should appear.
Number? 8
2
4
6
8
public static void run() {
}
public static void run() {
IO.print("Number? ");
int num = IO.readInt();
for(int i = 2; i <= num; i += 2) {
IO.println(i);
}
}
The odd-integer answer is identical, except that it begins i
at 1.
for(int i = 1; i <= num; i += 2) {